Thursday, June 5, 2008

Fastest time?

It was a dark stormy night… A group of 5 friends was trapped on Hill A full of wild, crazy animals… They had no idea when the beasts will attack them… With a lamp that can only last for 30 seconds, they must move over to Hill B for safety... Unfortunately, the tree branch that linked the 2 hills together can only support 2 people at a time… Once they crossed over, 1 guy definitely had to bring over the lamp to the Hill A…

And of course, different people have different weight therefore; it will take them different timing to travel across… Guy A, the fastest guy needs only 1 second, Guy B needs 3 seconds, Guy C needs 6 seconds, Guy D needs 8 seconds, and Guy E need 12 seconds.

Example, if Guy E and Guy A move across to Hill B as a pair, it will take them 12 seconds.. And certainly, we will get the fastest to move back to Hill A to bring the lamp over.. So total, they had used up 13 seconds... Okie, here comes the question, "Which guy is more handsome in the picture?"
HAHAHA...
Kidding!! Can u move all the guys over within 30 seconds?

5 comments:

YY said...

Ai.. so difficult.. you sure got answer one or not? Or some stupid answer.... Smile

Su W.J said...

take aeroplane....

pwsiang said...

Whahaha.. Cfm can solve de.. forget to add in.. there is no runway..

Normally, people will take the fastest and the slowest to move across..

Hint.. Take both the fastest over first..

Will post the answer soon.. Smile

Anonymous said...

1 3 6 8 12
My ans:
1) 1s & 3s go over, 3s return - 4s total (1 at hillA, 3 6 8 12 hillB)
2) 12s & 8s go over, 1s return - 13s total (8 12 hillA, 1 3 6 hillB)
3) 6s go over, 1s return - 7s total (6 8 12 hillA, 1 3 hillB)
4) 3s & 1s go over - total 3s (All at hillA)

Total time: 4+13+7+3 = 27s hahahah

pwsiang said...

If 1s & 3s and 3s move back, total time is 6 sec, not 4sec.

Anyway.. u know the answer liao.. haha..